What fraction of a 0.5 m acetic acid solution will be in the protonated form at ph 5.1? the pka of acetic acid is 4.8?

The acetic acid will dissociate as

                     We will use Hendersen Hassalbalch's equation here

pH = pKa + log [salt] / [acid]

Where

[Acid] = concentration of protonated form

5.1 = 4.8 + log [salt] / [acid]

1.99=  [salt] / [acid]

[salt] +[acid] = 0.5

1.99 [acid] + [acid] = 0.5

[acid] = 0.167 M

[acid] / total concentration  = 0.167 / 0.5 = 0.33.4

So percentage = 33.4 % or approx 33 %

convalent bond :

is a chemical bond formed by the sharing of electron between 2 atoms.

it is the direct chemical bond between 2 atoms.

in bond formation atoms are involved here.

electrovalent bond:

is a chemical bond defined as electroststic attraction between 2 atoms.

it is the electrostatic attraction between 2 atoms.

in bond formation, ions are involved here.

hope it

and ur welcm

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that tool would be a compass