Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 3-hexanone.

solution:

A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg

 Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.  

Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.  

Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.  

they vary. it used to be meat, grain, bread, candy, beverages, donuts, and fruits/vegetables. now they added exercise in.

it is stable as it is in group 0 which have full outer shells of electrons