What is the temperature change in 355 ml of water upon absorption of 34 kj of heat? (the specific heat capacity of water is 4.184 j/(g⋅∘

The temperature change is 23 °C.

q = mCΔT

ΔT = q/(mC)

m = 355 g

∴ ΔT = (34 000 J)/(355 g × 4.184 J·°C⁻¹g⁻¹) = 23 °C

Note: The answer can have only two significant figures because that is all you gave for the amount of heat absorbed.

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

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