Amedical lab is testing a new anticancer drug on cancer cells. the drug stock solution concentration is 1.5×10−9m, and 1.00 ml of this solution will be delivered to a dish containing 2.0×105 cancer cells in 5.00 ml of aqueous fluid. what is the ratio of drug molecules to the number of cancer cells in the dish?

The ratio of drug molecules to the number of cancer cells in the dish is .

Further Explanation:

Concentration of various solutions can be expressed by various concentration terms. Some of such concentration terms are listed below.

Molarity is defined as moles of solute present in one litre of solution. It is represented by M and its unit is mol/L. The expression for molarity of solution is as follows:

                …… (1)

Rearrange equation (1) to calculate moles of solute.

                        …… (2)

Substitute for molarity of solution and 1.00 mL for volume of solution in equation (2) to calculate moles of drug.

According to Avogadro’s law, one mole of every substance has . These units can vary from question to question and can be atoms, molecules, or formula units. Since one mole of drug also contains   , number of molecules of drug present in can be calculated as follows:

The ratio of drug molecules to the number of cancer cells in the dish can be evaluated as follows:

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration

Keywords: concentration, concentration terms, solutions, molarity, Avogadro’s law, drug molecules, cancer cells, 4.5*10^6, one mole, atoms, molecules.