Calculate the radius of a tantalum (ta) atom, given that ta has a bcc crystal structure, a density of 16.6 g/cm3 , and an atomic weight if 180.9 g/mol. (avogadro number, 6.023 ×1023 atoms/mol) (4pts)

The study of chemicals is called chemistry. The elemental weight of an atom is called atomic weight.

The correct answer to the question is 0.1432.

The data is given as follows:-

The formula used to solve the question is as follows:-

Placed all the value into the question and find the value of R.

Thus the correct answer is 0.1432nm.

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It is given that Ta has BCC crystal structure. The density is , atomic mass is 180.9 g/mol and Avogadro's number is atoms per mol.

The expression for density is as follows:

Here, n is number of atoms per unit cell, A is atomic number, is volume and is Avogadro's number .

Expression for volume is as follows:

For BCC, number of atoms per unit cell is 2, putting the values,

On rearranging,

Thus,

Since,

Thus,

Therefore, radius of tantalum atom is 0.1432 nm.

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