Solutions of hydrogen in palladium may be formed by exposing pd metal to h2 gas. the concentration of hydrogen in the palladium depends on the pressure of h2 gas applied, but in a more complex fashion than can be described by henry's law. under certain conditions, 0.94 g of hydrogen gas is dissolved in 215 g of palladium metal. (a) determine the molarity of this solution (solution density

Answer is: molarity of the solution is 3.902 M.

m(H₂) = 0.94 g; mass of hydrogen.

n(H₂) = m(H₂) ÷ M(H₂).

n(H₂) = 0.94 g ÷ 2.016 g/mol.

n(H₂) = 0.466 mol; amount of substance.

d(Pd) = 1.8 g/cm³; density of palladium.

V(Pd) = m(Pd) ÷ d(Pd).

V(Pd) = 215 g ÷ 1.8 g/cm³.

V(Pd) = 119.44 cm³ ÷ 1000 cm³/L = 0.11944; volume of palladium.

c = n(H₂) ÷ V(Pd).

c = 0.466 mol ÷ 0.11944 L.

c = 3.902 mol/L.

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