If 8.97 grams of (nh4)2co3 is used to make a 0.250-molar solution, what is the final volume of the solution?

               0.3733 L or 373 mL

Solution:

Data Given:

                  Mass  =  8.97 g

                  M.Mass of (NH₄)₂CO₃  =  96.09 g.mol⁻¹

                  Molarity  =  0.250 mol.L⁻¹

Step 1: Calculate Moles of Ammonium Carbonate as,

                        Moles  =  Mass ÷ M.Mass

Putting values,

                        Moles  =  8.97 g ÷ 96.09 g.mol⁻¹

                        Moles  =  0.0933 mol

Step 2: Calculate Volume of Solution as,

                        Molarity  =  Moles ÷ Volume

Solving for Volume,

                        Volume  =  Mole ÷ Molarity

Putting values,

                        Volume  =  0.0933 mol ÷ 0.250 mol.L⁻¹

                        Volume  = 0.3733 L

Or,

                       Volume  =  373 mL

explanation:

crosscutting concepts have application across all domains of science. as such, they are a way of linking the different domains of science. they include patterns; cause and effect; scale, proportion, and quantity; systems and system models; energy and matter; structure and function; and stability and change.