A0.77 mg sample of nitrogen reacts with chlorine to form 6.615 mg of the chloride. part a what is the empirical formula of the nitrogen chloride?

From the given:

Reacted mass of nitrogen = 0.77 mg

Mass of chlorine = 6.615 mg

Reacted mass of chlorine = 6.615 mg - 0.77 = 5.84 mg

Each value is divided by small number

Therefore, empirical formula is

The empirical formula of the nitrogen chloride is

Explanation:

Step 1: Form the formation equation of nitrogen chloride. The N and Cl are diatomic molecules, so they have subindices 2. We balance the chemical equation remaining:

+ 3 ->  

Step 2: We calculate the number of moles that are used from and the number of moles that we get from  .

moles of = 0,77mg * 1g/(1000mg) * 1/(28 g /mol )

moles of = 2,75 * 10^(-5)

moles of   = 6,615mg 2NCl3 * 1g/(1000mg) * 1/(28 g  /mol  )

moles of   = 5,5*10^(-5)

Step 3: We verify that the number of moles formed is correct using the reaction balance coefficients, taking into account that 1 mol of produces 2 moles of  .

2.75 * 10^(-5) moles of = (5.5*10^(-5) moles of  ) / 2

2,75 * 10^(-5) moles = 2,75 * 10^(-5) moles

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metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.