On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35cl and 86.15 % for 37cl. what is the atomic mass of chlorine for this location? the mass of 35cl is 34.9700 amu . the mass of 37cl is 36.9700 amu . express your answer to two decimal places, and include the appropriate u

              36.70 amu

Data Given:

                       Atomic Mass of ³⁵Cl  =  34.9700 amu

                       Natural Abundance of ³⁵Cl  =  13.85 %

                       Atomic Mass of ³⁷Cl  =  36.9700 amu

                       Natural Abundance of ³⁷Cl  =  86.15 %

Formula Used:

Average Atomic Mass  =  [(Atomic Mass of ³⁵Cl × Natural Abundance of ³⁵Cl) + (Atomic Mass of ³⁷Cl × Natural Abundance of ³⁷Cl)] ÷ 100

Putting values,

Average Atomic Mass  =  [(34.9700 × 13.85) + (36.9700 × 86.15)] ÷ 100

Average Atomic Mass  =  [(484.3345) + (3184.9655)] ÷ 100

Average Atomic Mass  =  3669.3 ÷ 100

Average Atomic Mass  =  36.70 amu

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alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.