Silver chloride, often used in silver plating, contains 75.27% ag. calculate the mass of silver chloride required to plate 255 mg of pure silver.

In silver chloride used for silver plating, 75.27% of Ag is present. Therefore, in 1 mole of AgCl, there are 0.7527 mol of Ag present.

Or, 1 mol of Ag is obtained from of AgCl.

Mass of pure silver given is 255 mg, converting mass into number of moles as follows:

here, n is number of moles, m is mass and M is molar mass.

Putting the values,

Thus, number of moles of Ag are 0.002364 mol.

Now, 0.002364 mol of Ag will be obtained from mol of AgCl.

Molar mass of AgCl is 143.32 g/mol, converting number of moles into mass as follows:

Converting mass into mg,

Therefore, mass of silver chloride required to plate 255 mg of pure silver will be 450 mg.

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1 is the answer to this problem