Asample of sodium reacts completely with 0.426 kg of chlorine, forming 702 g of sodium chloride. what mass of sodium reacted? express your answer to three significant figures and include the appropriate units.

The given reaction is:

First, calculate the number of moles of sodium chloride.

Number of moles  =

Molar mass of sodium chloride  =

Number of moles of =

=

Now, from the reaction; two moles of sodium gives two moles of sodium chloride.

So, 12 moles of sodium chloride needed = moles of sodium.

Thus, number of moles of sodium = moles

Now, mass of sodium  =

=

=

Thus, mass of sodium  =

276 grams of sodium reacted with 0.426 kg of chlorine to form 702 g of sodium chloride.

This is an example of a simple stoichiometry problem.

To determine the mass of sodium that reacted, two paths may be used:

To solve this problem, first write the balanced chemical equation:

2Na + Cl₂ → 2 NaCl

Based on the stoichiometric ratio, we can determine the mass of sodium that reacted through dimensional analysis.

1) Using the stoichiometric ratio of sodium and chlorine

2) Using the stoichiometric ratio of sodium and sodium chloride

Since the mass of Na is required to be given in three significant figures, then the final answer is:

Keywords: stoichiometry, moles

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