Nicotine, a component of tobacco, is composed of c, h, and n. a 2.625-mg sample of nicotine was combusted, producing 7.1210 mg of co2 and 2.042 mg of h2o. what is the empirical formula for nicotine?

The mass sample of nicotine combusted = 2.625 mg  (given)

Mass of produced = 7.1210 mg  (given)

Mass of produced = 2.042 mg  (given)

Molar mass of = 44 g/mol

Molar mass of = 18 g/mol

Percentage of Carbon = %

Percentage of hydrogen = %

Now, for percentage of nitrogen = %

Calculating the moles of each element:

Dividing with the smallest mole value to calculate the molar ratio of each element:

Hence, the empirical formula for nicotine is .