Hydrogen sulfide is an impurity in natural gas that must be removed. one common removal method is called the claus process, which relies on the reaction 8h2s(g)+4o2(g)→s8(l)+8h2o(g)under optimal conditions the claus process give 98% yield of s8 from h2s. if you started with 30.0 grams of h2s and 50.0 grams of o2, how many grams of s8 would be produced, assuming 98% yield

Given the yield is 98%

The reaction is

8H2S(g)+4O2(g)→ S8(l)+8H2O(g)

As per balanced equation eight moles of H2S will react with four moles of O2 to give one mole of S8

Let us calculate the moles of each reactant from given masses

30.0 grams of h2s

Moles = Mass / Molar mass = 30 / 34 = 0.88 moles

They need 0.44 moles of O2 to react

As 50.0 grams of o2  are given so

Moles = Mass / Molar mass = 50 / 16 = 3.125 moles

Thus H2S is the limiting reagent

8 moles of H2S will give one mole of S8

So 0.88 moles of H2S will give = 1 X 0.88 / 8 moles of S8 = 0.11 moles

However the yield is 98% so the actual moles of S8 formed = 0.98 X 0.11 = 0.1078 moles of S8

Mass of S8 produced = Moles X molar mass = 0.1078 X 256

= 27.6 grams of S8

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.