What is the theoretical yield of bromobenzene in this reaction when 32.0 g of benzene reacts with 69.3 g of bromine?

First calculate the number of moles of bromine and benzene.

Number of moles =

Mass of benzene = (given)

Molar mass of benzene=  

Substitute the above values in formula, we get

Number of moles of benzene=

=

Mass of bromine = 69.3 g

Molar mass of bromine = =

Substitute the above values in formula, we get

Number of moles of benzene=

=

Now, ratio of benzene and bromine comes out be 1:1 respectively and limiting reagent is benzene because present less as compared to bromine.

Thus, number of moles of bromobenzene =

Theoretical yield =

=   (molar mass of bromonenzene = 157.02 g/mol)

=

Hence, theoretical yield of bromobenzene is