The human body obtains 915 kj of energy from a candy bar. part a if this energy were used to vaporize water at 100.0 ∘c, how much water (in liters) could be vaporized? (assume the density of water is 1.00 g/ml

Given the energy obtained by the human body from a candy bar = 915 kJ

Energy required to vaporize 1 g of water at it's boiling point is referred to as heat of vaporization of water.

The heat of vaporization of water = 2260 J/g

Mass of water that can be vaporized by 915 kJ of heat =

Density of water = 1 g/mL

Converting mass to volume in L of 405 g water:

Therefore, 0.405 L of water can be vaporized

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'