The reaction of 9.2 grams of fluorine with excess chlorine produced 6.3 grams of clf3. what percent yield of clf3 was obtained? answer in units of %.

              %age Yield  =  20.12 %

Solution:

The Balance Chemical Reaction is as follow,

                                          Cl₂  +   3 F₂    →    2  ClF₃

According to Equation ,

              114 g (3 mole) F₂ produces  =  184.88 g (2 moles) of ClF₃

So,

                       19.2 g of F₂ will produce  =  X g of ClF₃

Solving for X,

                      X =  (19.2 g × 184.88 g) ÷ 114 g

                      X  =  31.13 g of ClF₃   (Theoretical Yield)

As we know,

                     %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

                     %age Yield  =  (6.3 g ÷ 31.3 g) × 100

                     %age Yield  =  20.12 %

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