You are given a 1.50 g mixture of sodium nitrate and sodium chloride. you dissolve this mixture into 100. ml of water and then add an excess of 0.500 m silver nitrate solution. the white solid produced from the reaction is filtered, dried and measured. the white solid has a mass of 0.641 g. calculate the percent, by mass, of sodium chloride in the original unknown mixture.

When AgNO₃ solution is added to mixture of NaNO₃ and NaCl, it reacts with NaCl and gives precipitate of AgCl, which is white solid. The reaction takes place in 1:1 stoicheometric ratio as per the following balanced reaction:

NaCl + AgNO₃→ AgCl ↓ + NaNO₃. As per reaction 1 mole NaCl reacts with 1 mole AgNO₃ and gives  of solid precipitate of 1 mole AgCl.

0.641 g= = 4.47 X mole of solid AgCl is produced. This indicates 4.47 X mole NaCl = g of Nacl reacts to give 0.641 g of AgCl. So, mass percentage of NaCl present in mixture== 17.33 %.

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be