Acar moves 5 km to the east, then 3 km to the north, and then 1 km to the east again. what is his displacement from his original position? write your answer to the nearest tenth. don't forget to include direction.

The displacement is 6.7 km to the northeast.

Displacement = 5 km + 1 km = 6 km to the east and 3 km to the north.

The net displacement is the hypotenuse of a right-angled triangle with sides

6 km and 3 km.

According to Pythagoras’ Theorem,

a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the other two sides.

c^2 = (6 km)^2 + (3km)^2 = 36 km^2 + 9 km^2 = 45 km^2

c = √(45 km^2) = 6.7 km NE

2b2t

explanation:

2b2t

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8