Chemistry, 12.07.2019 02:00 Jasten

Acompound contains only carbon, hydrogen, and oxygen. combustion of 9.612 mg of the compound yields 14.41 mg co2 and 3.93 mg h2o. the molar mass of the compound is 176.1 g/mol. what are the empirical and molecular formulas of the compound? (type your answer using the format co2 for co2.)

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Answer from: shiiIjustneedananswe

Formula used for determining the number of moles:

number of moles = $\frac{mass}{molar mass}$ -(1)

Mass of CO_2 = 14.41 mg (given)

Mass of H_2O = 3.93 mg (given)

Number of moles of from CO_2 = $\frac{14.41 \times 10^{-3} g}{44 g/mol}$

= $0.3275\times 10^{-3} mol$

Number of moles of from H_2O = $\frac{2 \times 3.93 \times 10^{-3} g}{18 g/mol}$

= $0.437\times 10^{-3} mol$

Mass of carbon = $0.3275\times 10^{-3} mol \times 12 g /mol$

= $3.93 \times 10^{-3} g$

Mass of hydrogen = $0.437 \times 10^{-3} mol \times 1 g /mol$

= $0.437 \times 10^{-3} g$

Mass of oxygen = total mass of the compound - mass of carbon- mass of hydrogen

= $9.612 \times 10^{-3} g- 3.93 \times 10^{-3} g - 0.437 \times 10^{-3} g$

= $5.245 \times 10^{-3}g$

Now, number of moles of oxygen = $\frac{5.245 \times 10^{-3} g}{16 g/mol}$

= $0.328 \times 10^{-3}g$

To identify the empirical formula; divide the number of moles of carbon, hydrogen and oxygen with least number of moles.

Thus,

$C_{\frac{0.3275\times 10^{-3} }{0.3275\times 10^{-3} }}$

$H_{\frac{0.437\times 10^{-3} }{0.3275\times 10^{-3} }}$

$O_{\frac{0.328\times 10^{-3} }{0.3275\times 10^{-3} }}$

$C_{1}H_{1.33}O_{1.00}$

Now, multiply the numbers with 3 to get the hydrogen number in whole number, we get

The empirical formula = $C_{3}H_{4}O_{3}$

The empirical weight = $3\times 12 g/mol+4\times 1 g/mol+3\times 16 g/mol$

= 88 g/mol

Divide the molecular weight with empirical weight to find the factor between empirical formula and molecular formula , we get

$\frac{molecular weight}{empirical weight}$ = $\frac{176.1 g/mol}{88 g/mol}$

Now, multiply the numbers of carbon, hydrogen and oxygen with 2 to get molecular formula, we get

Number of carbon = 6

Number of hydrogen = 8

Number of oxygen = 6

Thus, molecular formula is $C_{6}H_{8}O_{6}$ .

Answer from: Quest

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.

Answer from: Quest

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

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Acompound contains only carbon, hydrogen, and oxygen. combustion of 9.612 mg of the compound yields...

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