Given the balanced equation: 2 h2(g) + o2(g) → 2 h2o(l) how many grams of h2o are formed if 9.00 mol h2(g) reacts completely with an excess of o2(g)? the molar mass of h2o is 18.0 g/mol.

             162 g of H₂O

Solution:

The Balance Chemical Equation is as follow,

                                     2 H₂  +  O₂    →    2 H₂O

According to equation when,

                         2 mol of H₂ is reacted  =  36 g (2 mol) H₂O is produced

So,

     9 mol H₂ on reaction will produce  =  X g of H₂O

Solving for X,

                    X =  (9 mol × 36 g) ÷ 2 mol

                    X =  162 g of H₂O

answer; i believe that the correct answer is (a) potassium(k)