From a laboratory process, a student collects 28.0 g of hydrogen and 224.0 g of oxygen. how much water was originally involved in the process?

Chemical reaction is given as :

Here, 2 moles of water gives 2 moles of hydrogen and one mole of oxygen.

Mass of hydrogen =  28.0 g (given)

Mass of oxygen = 224.0 g (given)

Number of moles =

Thus, number of moles of hydrogen =

= 14 moles of hydrogen

Number of moles of oxygen=

= 7 moles of oxygen

Now, to find the amount of water:

= 252 g of water.

Thus, amount of water is 252 g (involved in the process).

i have know clue i guess aluminum

i think lol

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.