3.6 grams of boron react with 1.0 grams of hydrogen to give 4.6 grams of bh3. how many grams of boron would react with 3.3 grams of

The mass of boron that will react with 3.3 g of Hydrogen is 11.88 g

From the question given above, we were told that 3.6 g of boron react with 1.0 g of hydrogen to give 4.6 grams of BH3.

With the above information in mind, we can obtain the mass of boron needed to react with 3.3 g of hydrogen. This can be obtained as follow:

From the question given above,

3.6 g of boron react with 1.0 g of hydrogen

Therefore, Xg of boron will react with 3.3 g of Hydrogen i.e

Xg of boron = 3.6 × 3.3

Thus, we can conclude that 11.88 g of boron will react with 3.3 g of Hydrogen

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The hydrogen will react with 12 g B

Mass of B = 3.3 g H_2 × (3.6 g B/1.0 g H_2) = 12 g B

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  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-