Read the following chemical equation. al + cl2 → alcl3 which of the following fractions can be used for the mole ratio to determine the mass of al from a known mass of alcl3? a. 2/1 b. 3/2 c. 2/2 d. 2/3

The fraction for the determination of mass of Aluminum from known mass of aluminum chloride has been 2/2. Hence, option C is correct.

The mole ratio has been defined as the ratio of the moles of one substance with respect to the moles of another substance.

The given reaction has been:

For the determination of the mole ratio from the chemical reaction, the reaction has been balanced.

The balanced chemical reaction has been:

From the balanced chemical equation, for 2 moles of aluminum chloride, 2 moles of Al have been used. Thus, the Al used for the x moles of known aluminum chloride has been:

Thus, the fraction for the determination of mass of Aluminum from known mass of aluminum chloride has been 2/2. Hence, option C is correct.

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C. 2/2

a)Balance the chemical equation

2Al + 3Cl2 → 2AlCl3

b)We want to convert moles of AlCl3 to moles of Al

The conversion factor is either 2 mol Al/2 mol AlCl3 or 2 mol AlCl3/2 mol Al.

We choose the one that makes the units cancel:

x mol AlCl3 x (2 mol Al)/(2mol AlCl3) = x mol Al

The fraction for the molar ratio is 2/2.

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it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2