Magnesium (mg) is a valuable metal used in alloys, in batteries, and in the manufacture of chemicals. it is obtained mostly from seawater, which contains about 1.30 g of mg for every kilogram of seawater. calculate the volume of seawater (in liters) needed to extract 5.33 × 104 tons of mg. seawater has a density of 1.03 g/ml. (1 ton = 2000 lb; 1 lb = 453.6 g) enter your answer in scientific notation.

Given that, 1.30 g of mg per kg (1000 g) of sea water.

Convert into gram.

1 ton = 2000 lb

Thus,

 =

= =

1 lb = 453.6 g

Thus,

=

= =

Now,

1.30 g of magnesium is present in  1000 g of seawater.

Thus, 1 g of magnesium present in of seawater.

of magnesium present in =  

= of seawater.

Now, density of sea water is

Density is equal to the ratio of mass and volume.

Put the value of density and mass to find the volume:

Volume =

Volume =

Now, convert ml into L:

1 L = 1000 ml

Volume in L =

=

Thus, volume in litres =

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.