A0.4230 g sample of impure sodium nitrate (contains sodium nitrate plus inert ingredients) was heated, converting all the sodium nitrate to 0.2820 g of sodium nitrite and oxygen gas. determine the percent of sodium nitrate in the original sample.

Percent of sodium nitrate is 82.13%

Explanation:

Number of moles of a compound is the ratio of mass of the compound to molar mass of the compound.

Molar mass of = 68.9953 g/mol

Molar mass of = 84.9947 g/mol

So, 0.2820 g = moles of    = 0.004087 moles of  

Above equation suggests, 1 mol of    is formed from 1 mol of  

So, 0.004087 moles of   are formed from 0.004087 moles of  

So, mass of 0.004087 moles of   =

% of  in sample = % = %

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