Which of these items best describes the arrangement of electrons in an atom of sulfur? a. eight electrons in its first energy level; eight valence electrons in its outermost shell b. two electrons in its first energy level; two electrons in its second energy level; eight electrons in its third energy level; four valence electrons in its outermost energy level c. two valence electrons in its first energy level; eight electrons in its second energy level; six electrons in its outermost energy level d. two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level

The correct answer is Option D.

Explanation:

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

Sulfur is the 16th element of the periodic table having 16 electrons. The electronic configuration of this element is:

The number of electrons in first shell (n = 1) : 2

The number of electrons in second shell (n = 2) : (2 + 6) = 8

The number of electrons in third shell, outermost shell (n = 3) : (2 + 4) = 6

The number of valence electrons in sulfur atom are 6

Hence, the correct answer is Option D.

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→