When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. how many grams of sodium sulfide are formed if 1.5 g of hydrogen?

According to the reaction equation:

H2S + 2NaOH = Na2S + 2 H2O

1-first we need to get moles of H2S:

moles H2S = mass / molar mass

moles H2S = 1.5 g /34.082 g/mol=0.044 moles

2- then we need to get moles of NaOH:

moles of NaOH = mass / molar mass

= 2 g / 40 g/mol=0.05 g

when NaOH is the limiting reactant 0.0440 x 2 = 0.0880 moles needed

- and moles Na2S = 0.0500/2 = 0.0250

mass Na2S = moles Na2S / molar mass

0.0250 x 78.0456 g/mol = 1.95 g

3- assuming 92.0 % yield:

1.95 x 92.0/100 = 1.80 g

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