How many grams of water at 50◦c must be added to 16 grams of ice at −12◦c to result in only liquid water at 0◦c?

When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.

- Heat given out by water = Heat absorbed by ice

Calculating the heat released by hot water:

ΔT

Calculating heat absorbed by 16 g of ice: Ice at is converted to ice at and then ice at to water at

ΔT +

+

q = 405.12 J +5336.8 J =5741.92 J

- Heat given out by water = Heat absorbed by ice

-(

m = 27.4 g

Therefore, 27.4 g water at must be added to 16 g of ice at to convert to liquid water at

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

particle   p is an electron and particle q is a neutron