Answers: 1
![pH=-\log[H^+]](/tpl/images/0086/2902/cf945.png)
of sulfuric acid will give .![[H^+]=2\times 1.0\times 10^{-4} M=2.0\times 10^{-4} M](/tpl/images/0086/2902/95a1c.png)
![pH=-\log[2.0\times 10^{-4} M]=3.70](/tpl/images/0086/2902/fb91e.png)
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What is the ph of a 1.0 x 10^-4 m solution of sulfuric acid (h2so4)?...
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