If a reaction vessel initially contains 5 mols and 10 molo2, how many moles of s will be in the reaction vessel once the reactants have reacted as much as possible? (assume 100% actual yield.)

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Zero

Explanation: -

Number of moles of sulphur S = 5 mol

Number of moles of O2 = 10 mol

The reaction between them will be synthesis type.

The product formed will be SO2.

The balanced chemical equation for this chemical reaction is

S + O2 -- > SO2

From the balanced equation we see that

1 mol of S reacts with 1 mol of O2

So, 5 mol of S will react with

= 5 mol of O2.

O2 left = 10 – 5 = 5 mol

Sulphur is limiting reagent and will be used up

b is the correct