Chem consider the reaction: ? li(s)+? n2(> ? li3n(s) calculate the mass of lithium nitride formed from 33.6524g of nitrogen gas and 58.7032g lithium

Considering the equation:

Li(s)+N₂(g)—->Li₃N(s)

Balancing this equation will give :

6Li(s)+N₂(g)—->2Li₃N(s)

It can be seen that 6 mol of Li reacts with 1 mol of N₂to produce 2 mol of Li₃N.

Here 33.6524g of nitrogen gas reacts with 58.7032g lithium to produce Li₃N.

Moles of Li = 58.7032 g *

Moles of

Mass of

Mass of = 1.2 mol * \frac{2 mol Li_{3}N}{1 mol N2}* \frac{34.83 g Li_{3}N}{1 mol Li_{3}N} = 98.2 g " alt=" N_{2}" /> = 1.2 mol * \frac{2 mol Li_{3}N}{1 mol N2}* \frac{34.83 g Li_{3}N}{1 mol Li_{3}N} = 98.2 g " /> = 83.6 g

there are two significant figures.