Use the periodic to write the electron configuration for rubidium (rb) in noble-gas notation. rb: [kr]s

-

[Kr] 5s1

Explanation:-

Atomic number of rubidium = 37

Atomic number of Kr = 36

So only 1 electron needs to be assigned an orbital.

Kr is also the last element of the fourth period

So the shell number for the 1 electron will be 5 since it is after Kr

Since s subshell is filled first the electron will go into 5s.

Hence the electron configuration for rubidium (Rb) in noble-gas notation is

[Kr] 5s1

i do not get it   at all

girl imma just put my comment here because i need a couple point okurrttt