Acommercial refrigeration unit accidentally releases 7.68x10^1 ml of ammonia gas at satp. determine the mass and number of ammonia molecules released.

-

0.0583 g and 2.064 x 10²⁰ molecules of ammonia are released when a commercial refrigeration unit accidentally releases 7.68 x 10¹ mL of ammonia gas at STP

Explanation: -

Volume of ammonia gas released = 7.68 x 10¹ mL

= 76.8 mL

=

= 0.0768 L

We know that at STP standard temperature and pressure,

22.4 L of a gas has 6.02 x 10²³ molecules of ammonia.

0.0768 L of a gas is occupied by

= 2.064 x 10²⁰ molecules of ammonia

Molar mass of NH₃ = 14 x 1 + 1 x 3 = 17 g.

At STP, we know

22. 4 L of ammonia has 17 g of ammonia.

0.0768 L of ammonia has

=0.0583 g of ammonia.

∴ 0.0583 g and 2.064 x 10²⁰ molecules of ammonia are released when a commercial refrigeration unit accidentally releases 7.68 x 10¹ mL of ammonia gas at STP

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3