What is the ph of a 2.00 m hno2 solution if ka=5.00 e-6?

-

2.5

Explanation: -

Initial [HNO₂] = 2.00 M

ka = 5.00 x 10 ⁻⁶

ICE table for HNO₂ =

[

Ka =

5.00 x 10-6 =

x = 0.0032 M

pH = - log [H⁺]

= - log 0.0032

= 2.5

explanation:

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