Write the electron dot structure for potassium and chlorine show the formation of kcl by the transfer of electrons name the ions present in the compound, kcl

Answer : The correct answer for ions present in KCl is K⁺ and Cl⁻ which forms KCl by ionic bond (complete transfer of electron from K to Cl ) .

The electron dot structure : It is representation of valence electrons around the symbol of atoms.

Potassium : As it belongs to s -block , the electronic configuration of potassium is 1s² 2s² 2p⁶ 3s² 3p⁶4s¹ .Since Potassium has 1 electron in its outermost shell , so its electron dot structure involves K with one dot .

Chlorine : Chlorine belongs to p-block so the electronic configuration of Cl is 1s² 2s² 2p⁶ 3s² 3p⁵ . The valence electrons present in Cl is 7 , so the electron dot structure of Cl involves 7 dots around Cl .

The electron dot structures are shown in image.

Potassium chloride : It is ionic compound and formed by ionic bond between two ions , cations and anion . Cation is potassium and anion is chlorine.

Potassium being a metal , have tendency to donate the electron and form a cation . Since the outer shell has only 1 electron in it , so K easily loose this electron to gain stable configuration and form K⁺ ion .

Chlorine is a non metal and electronegative element ,so it has tendency to accept electron. and form anions. The electronic configuration of Cl is 1s² 2s² 2p⁶ 3s² 3p⁵ , that is , it is one electron short to complete the octet . Hence , it easily accepts one electron and form anion Cl⁻.

Potassium give its electron to Cl and forms ionic bond between K⁺ ion and Cl⁻ ion by complete transfer of one electron to form potassium chloride .(shown in image )

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"