An electrochemical cell has the following overall reaction: mn(s) + cu2+(aq) > cu(s) + mn2+(aq) the reduction half-reaction has a standard potential of 1.18 v. the oxidation half-reaction has a standard potential of 0.34 v. what is the overall cell potential? (a) -1.52 v (b) -1.18 v (c) +1.18 v (d) +1.52 v

Oxidation is a process in which electrons are lost from the substance. Since electrons are lost, oxidation state increases.

In the above reaction, we can see that oxidation state increases for Mn from 0 to +2. That mean Mn is undergoing oxidation.

We have

The oxidation state decreases for Cu, that means Cu undergoes reduction.

The formula to calculate cell potential is

Let us plug in the given Eox and Ered values.

The overall cell potential is +1.52V

you did not give any options thus this is the best answer i can give to you with this little information you have given

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