When 5.0 mol al react with 13 mol hcl, what is the limiting reactant, and how many moles of alcl3 can be formed? (2 points) 2al + 6hcl → 2alcl 3 + 3 h 2 al is the limiting reactant; 5.0 mol alcl3 can be formed hcl is the limiting reactant; 4.3 mol alcl3 can be formed al is the limiting reactant; 7.5 mol alcl3 can be formed hcl is the limiting reactant; 6.5 mol alcl3 can be formed

Well, we need to find the ratio of Al to the other reactant.

Al:HCl = 1:3

--> this means that for every 1 Al used, you have to use 3 HCl.

5*3 = 15 moles of HCl needed to fully react with 5 moles of Al. Since 13<15, HCL is the limiting reactant.

The ratio of HCl:AlCl = 3:1

13/3 = 4.3333...

The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced so choice B.

Hope this helps!!! :)

the answer is option a.