Areaction has an activation energy of 195.0 kj/mol. when the temperature is increased from 200. °c to 220.°c, the rate constant will increase by a factor of

The rate constant will increase by a factor of 6.5.

Using the Arrhenius equation;

ln(k2/k1) = -Ea/R(1/T2 - 1/T1)

k1 = rate constant at 200. °c

k2 = rate constant at 220.°c

Ea = Activation energy

T2 =  220.°c or 493 K

T1 = 200. °c or 473 K

Hence;

ln(k2/k1) = -195.0 × 10^3/8.314(1/493 - 1/473)

k2/k1 = 6.5

Hence;

k2 = 6.5k1

The rate constant will increase by a factor of 6.5.

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Answer : The rate constant will increase by a factor of 7.5

Explanation :

The relationship between Temperature and rate constant can be explained with the help of Arrhenius equation. The equation is given below.

㏑ (k₂/k₁) = - Ea/R ( 1/T₂ - 1/T₁)

Here k₁ & k₂ represent rate constants at temperatures T₁ and T₂

The temperature is expressed in Kelvin unit

Ea is activation energy which is expressed in J/mol

R is gas constant which is 8.314 J mol⁻¹ K⁻¹

Here we know that T₁ is initial temperature which is 200° C

To convert Celsius to Kelvin we add 273

Therefore T₁ = 200 + 273 = 473 K

T₂ = 220 + 273 = 493 K

Ea = 195 kJ/mol . We will convert kJ to J

The conversion factor is 1 kJ = 1000 J

195 kJ × (1000 J / 1 kJ) = 195000 J

So Ea = 195000 J

Let us plug in these values in Arrhenius equation now.

ln k₂/k₁ = - 195000 J mol⁻¹ / 8.314 J mol⁻¹ K⁻¹ ( 1/493 K - 1/473 K)

ln k₂/k₁ = - 23454.4 ( 0.0020284 - 0.0021142)

ln k₂/k₁ = -23454.4 × ( -8.58 × 10⁻⁵)

ln k₂/k₁ = 2.012

k₂/k₁ = e^ (2.012)

k₂/k₁ = 7.48

The above answer can be rounded to 7.5

Therefore we have k₂/k₁ = 7.5

k₂ = 7.5 k₁

We know that k₂ is the rate constant at 220° C and k₁ is the rate constant at 200°C.

Therefore we can say that the rate constant will increase by a factor of 7.5

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.