Consider the balanced chemical equation 2c2h6+7o2 - 4co2+6h20. how many moles of h 2 o are produced when 1.0 mol of c 2h 6 reacts with excess o2?

1 mole C2H6 * (6mol H2O)/ 2 mole C2H6 = 3 mol H2O

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

your answer would be “dry”