Will give for the acids, use the formula ph = -log[h+]. (because hcl has 1 h+ ion per formula unit, [h+] equals the molarity.) for water, us what you know about the ph of neutral solutions. for the bases, examine and extend the pattern.

0.1M HCl              [H⁺]=0.1=10⁻¹       pH= - log 10⁻¹ = 1,  pH = 1
0.001M HCl          [H⁺]=0.001=10⁻³       pH= - log 10⁻³ = 3,  pH = 3
0.00001M HCl      [H⁺]=0.00001=10⁻⁵       pH= - log 10⁻⁵ = 5,  pH = 5
Distilled water                                           pH=7

0.00001 NaOH   [OH⁻]=10⁻⁵, [OH⁻][H⁺]=10⁻¹⁴, [H⁺]=10⁻¹⁴/10⁻⁵=10⁻⁹,
                           pH=9

0.001 NaOH   [OH⁻]=10⁻³, [OH⁻][H⁺]=10⁻¹⁴, [H⁺]=10⁻¹⁴/10⁻³=10⁻¹¹,
                           pH=11

0.1 NaOH   [OH⁻]=10⁻¹, [OH⁻][H⁺]=10⁻¹⁴, [H⁺]=10⁻¹⁴/10⁻¹=10⁻¹³,
                           pH=13

Yes it would be a physical change.

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is