Identify the spectator ions in this reaction. check all that apply. 2h+ + cro4– + ba2+ + 2oh– ba2+ + cro4– + 2h2o h+ cro4– ba2+ oh– 2h2o

CrO₄⁻ and  Ba²⁺


Explanation:


1) Chemical equation given:

2H⁺ + CrO₄⁻ + Ba²⁺ + 2OH⁻ → Ba²⁺ + CrO₄⁻ + 2H₂O


2) Analysis

That is an oxidation-reduction equation (some species are been oxidized and others are being reduced).

The given equation is known as total ionic equation, because it shows all the species as ions that are part of the reaction.

2) Specator ions

Spectator ions are the ions that do not change their oxidation state and are easily identified as they are the same in the reactant and product sides.

Here the ions that are the same in the reactant and product sides are:

CrO₄⁻ and  Ba²⁺


3) Addtitional explanation.


Once you identify the spectator ions you can delete them from the equation to obtain the net ionic equation , which in this case turns to be:


2H⁺ + 2OH⁻ →  2H₂O

But this is  not part of the question; it is some context to help you  understand the use of the spectator ions concept.

It shows that the experiment is designed properly.