The mineral stibnite, antimony(iii) sulfide, is treated with hydrochloric acid to give antimony(iii) chloride and what mass of sbcl3 is produced from a 3.35 g sample of stibnite? hydrogen sulfide gas.

4.50 g.

Explanation:

1) Chemical reaction

antimony(III) sulfide + hydrochloric acid → antimony(III) chloride and hydrogen sulfide gas.

Sb₂S₃ + HCl → SbCl₃ + H₂S

2) Balanced chemical equation

Sb₂S₃ + 6HCl → 2SbCl₃ +3H₂S

3) Mole ratio

1 mol Sb₂S₃ : 2SbCl₃

4) Convert 3.35 g sample of stibnite ton number of moles

Molar mass Sb₂S₃ = 339.715 g/mol

number of moles = mass in grams / molar mass = 3.35 g / 339.715 g/mol = 0.00986 mol

5) Proportion

1 mol Sb₂S₃ / 2 mol SbCl₃ = 0.00986 mol Sb₂S₃ / x

x = 0.01972 mol SbCl₃

6) Convert 0.01972 mol SbCl₃ to grams

molar mass SbCl₃ = 228.13 g/mol

mass in grams = molar mass × number of moles = 228.13 g/mol × 0.01972 mol = 4.50 g.

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

i belive it is water