How many grams of mgcl2 will be produced from 10.5g of mg(oh)2 and 41g of hcl?

The number  of grams  of MgCl2 that   will  be  produced  from 10.5 g Mg(OH)2 and 41 of HCl  is  17.154 grams

calculation

write the  equation  for reaction
 Mg(OH)2  + HCl →  MgCl2  +2H2O

find the moles of  each compound  used

moles=mass /molar mass

moles of  Mg(OH)2 =  10.5g/ 58.3 g/mol =  0.180  moles
moles  of  HCl =  41 g/ 36.5g/mol = 1.123  moles

by  use of of mole ratio between  Mg(OH)2 to  MgCl2  which  is 1:1  moles of MgCl2 is also   0.180  moles

by  use   of mole ratio  between  HCl  to  MgCl2 which is 2:1 the moles of MgCl2  = 1.123  x1/2 = 0.5615  moles

HCl  was  in excess  while  Mg(OH)2  was the  limiting reagent, therefore  moles  of  MgCl2 = 0.180 moles

mass of MgCl2= moles  MgCl2 x molar mass of MgCl2 (  24.3 + 35.5 x2=95.3)

mass =  0.180  x 95.3 = 17.154 grams

1. why does the same side of the moon always face earthc.the rotational period of the moon is equal to one revolution around earth2. which is greater the moons period of rotation or its period of revolution  b.the moons revolution period around earth3.what was the major accomplishment of the apollo missions  d.landing on and exploring the moon4. which of these space missions involved the deployment of lunar rovers d.apollo5. which scientists are going to explore next on kepler-186fd. evidence of existence of life6.which mission is not going to explore the outside of the solar systemb.safir7.which technology limit the future of space exploration b. scientist must first develop certain technologies before missions can be completed.

The answer is false because: gravitational force is independent of medium and depends only on the masses of the two objects and the distance between them