Consider the reaction h2so4 + 2 naoh -> na2so4 + 2h2o as it represents an acid-base tritration. the equivalence point occurs when 25.34 ml of 0.2767 m naoh is added to a 39.54 ml portion of h2so4. what is the molar concentration of h2so4 expressed in m?

We consider the given reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O as applies to an acid-base titration.
            moles NaOH = c · V = 0.2767 mmol/mL · 25.34 mL = 7.011578 mmol
            moles H2SO4 = 7.011578 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH
                                      = 3.505789 mmol
Hence
            [H2SO4]= n/V = 3.505789 mmol / 39.54 mL = 0.08866 M
The answer to this question is  [H2SO4] = 0.08866 M

Yes i think so not 100 percent sure though