Consider the reaction h2so4 + 2 naoh -> na2so4 + 2h2o. in an acid-base tritration, the stoichiometric point happens when 43.44 ml of 0.2753 m naoh is added to a 54.69 ml portion of h2so4. what is the molar concentration of h2so4 expressed in m?

            moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
            moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
            [H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is  [H2SO4] = 0.1093 M

Elias is almost correct. he just got it backwards.the correct answer is that it demonstrates elastic potential energy transforming into kinetic energy.