In the reaction h2so4 + 2 naoh -> na2so4 + 2h2o, an equivalence point occurs when 23.1 ml of 0.2055 m naoh is added to a 25.0 ml portion of h2so4. what is the [h2so4]?

            moles NaOH = c · V = 0.2055 mmol/mL · 23.1 mL = 4.74705 mmol
            moles H2SO4 = 4.74705 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.373525 mmol
Hence
            [H2SO4]= n/V = 2.373525 mmol / 25.0 mL = 0.09494 M
The answer to this question is  [H2SO4] = 0.09494 M

Order of filling levels and sublevels of electrons: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²3f¹⁴5d¹⁰6p⁶for an element with 5 electrons in the 3d energy level: full configuration: 1s²2s²2p⁶3s²3p³.