The molar mass of naoh is 40.00 g/mol. if 5.20 g naoh are dissolved in 0.500 l of solution what is the molarity of the solution

                         moles NaOH = 5.20 g * 1 mol / 40.00 g = 0.13 mol
                         [NaOH] = n/V = 0.13 mol / 0.500L
                                       = 0.26 M
The answer to this question is 0.26 M

Sorry i dont understand the question can you rephase it?

☆ionisation energy increases across a period from na -> ar☆ionisation energy decreases down a group from li -> fr☆ionic radius decreases across a period from na -> cl☆ionic radius increases down a groupfrom f -> ii hope it clarifies your doubts