Write the ground state electron configuration of b using the noble-gas shorthand notation

[He] 2s² 2p¹

Explanation:

1) B is boron

2) Atomic number of boron is 5, meaning that it has 5 protons and 5 electrons.

3) So, the ground state electron configuration is 1s² 2s² 2p¹

4) Using the noble-gas shorthand notation means that you start with the configuration of the noble gas previous to the element.

In this case, the noble gas that is before B is He.

So, the noble-gas shorthand notation for B is [He] 2s² 2p¹