In the combustion of ethane, shown above, how many moles of carbon dioxide can be produced from 1.00 mole of ethane? a. 0.500 mole b. 1.00 mole c. 2.00 moles d. 4.00 moles

The balanced chemical equation for the combustion of ethane is 
2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l)

The stoichiometric ratio between C₂H₆(g) and CO₂(g)  is 1 : 2

Hence,
    moles of CO₂(g) produced = moles of reacted C₂H₆(g) x 2
                                                  = 1.00 mol x 2
                                                  = 2.00 mol

Hence, the correct answer is "C".

If the water vapor content stays the same and the temperature drops, then the relative humidity increases. its vise versa.if the water vapor content stats the same and the temperature rises, the relative humidity decreases. so, yes, i'd say that temperature and humidity have a strong relationship.

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml