If water is added to 50 ml of a 0.04 m solution so that it fills a 200 ml beaker, what is the final concentration? m

Answer : The final concentration is, 0.01 mole/L or 0.01 M

Solution :

According to the neutralization law,

where,

= initial molarity (concentration) of solution = 0.04 M  = 0.04 mole/L

= initial volume of solution = 50 ml = 0.05 L

= final molarity (concentration) of solution = ?

= final volume of solution = 200 ml  = 0.2 L

Conversion : (1 L = 1000 ml)

Now put all the given values in the above law, we get the volume of NaOH solution.

Therefore, the final concentration is, 0.01 mole/L or 0.01 M

the answer is option a.

1 is the answer to this problem